关于字符操作符与位置参数结合问题

小钢蹦

大家好，这里是我实验的代码小弟初学，

2. stringZ=abcABC123ABCabc
3. echo "Scrip out shortest match between 'a' and 'C'"
4. echo "\${stringZ$1 a*C}:"
5. echo ${stringZ`$1` (a*C)}
6. echo "Strip out longest matech between 'a' and 'C'"
7. echo "\${stringZ$1a*C}:"
8. echo ${stringZ$1(a*C)}

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如何实现在string里获取positional parameters value?

2. echo ${stringZ$1(a*C)}

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上边那样写会报错，bad substitution
请问，./substring %
达到这样的效果
[code ]
${string% a*C}
[/code]