gcc编译问题

laurel2006

如下代码:
main()
{
printf("kldjfklsdjfkls
sdlkfjksldjflksdjf
sdfjsldkfjl\n");
}
用gcc3.3与gcc4.1.2进行编译，出现如下错误:
a.c: In function 'main':
a.c:3: error: missing terminating " character
a.c:4: error: 'sdkjfklsdjfkldjs' undeclared (first use in this function)
a.c:4: error: (Each undeclared identifier is reported only once
a.c:4: error: for each function it appears in.)
a.c:5: error: expected ')' before 'sdklfjlsdkflsdf'
a.c:5: error: stray '\' in program
a.c:5: error: missing terminating " character
a.c:6: error: expected ';' before '}' token
意思是，字符串不能换行，但在gcc2.7或2.9却可以编译通过，如何解决这个问题？在新版的gcc也能处理这个问题。

DoDo

1. 
   
2. char a[] = "\
   
3. abc\
   
4. def";
   
5. 
   
6. char b[] =
   
7. "abc"
   
8. "def";
   

复制代码

laurel2006

难道新版的GCC就不再支持这样的特性了?
有现成的shell脚本来完成这件事吗？因为有很多代码都有字符分行问题。