find, xargs传递的文件名参数中含有空格如何处理

ideawu

find . | xargs -n1 cat , 如果文件名中含有空格, 会被认为是两个文件, 请问如果处理? 谢谢?

lastart

find . -exec cat {} \;

ideawu

Post by lastart
find . -exec cat {} \;

谢谢.

因为查找到的数据还需要过滤, 所以我这样使用:
find . -exec echo '"{}"' \; 把路径用双引号包起来, 再往下传.

sssslang

find . -print0 | xargs -n1 -0 cat

man xargs:
Because  Unix  filenames  can contain blanks and newlines, this default
behaviour is often problematic; filenames containing blanks and/or new-
lines  are  incorrectly  processed by xargs.  In these situations it is
better to use the `-0' option, which  prevents  such  problems.    When
using  this  option you will need to ensure that the program which pro-
duces the input for xargs also uses a null character  as  a  separator.
If that program is GNU find for example, the `-print0' option does this
for you.

herro

find . -print | xargs -i echo '"{}"'